Объяснение:
(x²-y²)-(x²+2xy+y²)=(x-y)(x+y)-(x+y)²=(x+y)(x-y-(x+y))=
(x+y)(x-y-x-y)=-2y(x+y)
Ответ:
(x²-y²)-(x²+2xy+y²)=(х+у)(х-у)-(х+у)(х+у)=(х+у)(х-у-(х+у))=(х+у)(х-у-х-у)=(х+у)·(-2у)=-2у(х+у)
II- способ
(x²-y²)-(x²+2xy+y²)=x²-y²-x²-2xy-y²=-2у²-2ху=-2у(у+х)
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Answers & Comments
Объяснение:
(x²-y²)-(x²+2xy+y²)=(x-y)(x+y)-(x+y)²=(x+y)(x-y-(x+y))=
(x+y)(x-y-x-y)=-2y(x+y)
Ответ:
Объяснение:
(x²-y²)-(x²+2xy+y²)=(х+у)(х-у)-(х+у)(х+у)=(х+у)(х-у-(х+у))=(х+у)(х-у-х-у)=(х+у)·(-2у)=-2у(х+у)
II- способ
(x²-y²)-(x²+2xy+y²)=x²-y²-x²-2xy-y²=-2у²-2ху=-2у(у+х)