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ВадимЗинчук
@ВадимЗинчук
March 2022
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Выпоните действия 7класс срочно!
1) (2x+1/2x-1 - 2x-1/2x+1) : 8x/2x-1
2) (a+5/a-5 - a-5/a+5) : 2a/a^2-25
3) (1/x+1/y) : (1/x-1/y) - x+y/ x-y
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kratgv
Verified answer
1) (2x+1/2x-1 - 2x-1/2x+1) : 8x/2x-1=((2х+1)²-(2х-1)²)/4х²-1 : 8х/2х-1=
=((2х+1+2х-1)(2х+1-2х+1))/4х²-1 : 8х/2х-1=(4х·2)/4х²-1 : 8х/2х-1=8х/(2х+1)(2х-1) ·(2х-1)/8х=1/(2х+1)
2) (a+5/a-5 - a-5/a+5) : 2a/a²-25=((а+5)²-(а-5)²)/а²-25 : 2а/а²-25=(а+5+а-5)(а+5-а+5)/(а²-25) · (а²-25)/2а=(2а·10)/(а²-25) · (а²-25)/2а=10
3) (1/x+1/y) : (1/x-1/y) - x+y/ x-y=(у+х)/ху:(у-х)/ху=(у+х)/ху · ху/у-х=(у+х)/(у-х)
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Answers & Comments
Verified answer
1) (2x+1/2x-1 - 2x-1/2x+1) : 8x/2x-1=((2х+1)²-(2х-1)²)/4х²-1 : 8х/2х-1==((2х+1+2х-1)(2х+1-2х+1))/4х²-1 : 8х/2х-1=(4х·2)/4х²-1 : 8х/2х-1=8х/(2х+1)(2х-1) ·(2х-1)/8х=1/(2х+1)
2) (a+5/a-5 - a-5/a+5) : 2a/a²-25=((а+5)²-(а-5)²)/а²-25 : 2а/а²-25=(а+5+а-5)(а+5-а+5)/(а²-25) · (а²-25)/2а=(2а·10)/(а²-25) · (а²-25)/2а=10
3) (1/x+1/y) : (1/x-1/y) - x+y/ x-y=(у+х)/ху:(у-х)/ху=(у+х)/ху · ху/у-х=(у+х)/(у-х)