(x-y)(x+y)+2(2x-y)+3
= x² - y² + 2(2x-y)+3
= x² - y² + 4x - 2y + 3
= (x² + 4x + 4) - (y² + 2y + 1)
= (x+2)² - (y+1)²
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(x-y)(x+y)+2(2x-y)+3
= x² - y² + 2(2x-y)+3
= x² - y² + 4x - 2y + 3
= (x² + 4x + 4) - (y² + 2y + 1)
= (x+2)² - (y+1)²
=x?-y? +2(2x-y)+3
=×? - y? +4x - 2y + 3 = (x2+ 4× +4) - (y? + 2y + 1)
= (x+2)2 - (y+1)2
(Надіюсь правильно)