Вычислите x1/x2 + x2/x1, если x1 и x2 - корни уравнения 3x^2 - 8x - 15=0
D=64+180=244
x1=(8-2√61)/6=(4-√61)/3
x2=(8+2√61)/6=(4+√61)/3
x1/x2 + x2/x1 = ((4-√61)/3)/((4+√61)/3)+((4+√61)/3)/((4-√61)/3) = (4-√61)/(4+√61)+(4+√61)/(4-√61) = ((16-61)+(16+61))/((4+√61)(4-√61)) = 32/(16-61)=-32/45
3x^2 - 8x - 15=0
Δ=64-4*3*(-15)=244
√Δ=2√61
x1=(8-2√61)/6=4/3-1/3√61
x2=(8+2√61)/6=4/3+1/3√61
x1 x2 4/3-1/3√61 4/3+1/3√61
--- + --- = ---------------- + ----------------- =
x2 x1 4/3+1/3√61 4/3-1/3√61
(4/3-1/3√61)(4/3-1/3√61) (4/3+1/3√61)(4/3+1/3√61)
= --------------------------------- + ---------------------------------- =
(4/3+1/3√61)(4/3-1/3√61) (4/3-1/3√61)(4/3+1/3√61)
16/9-8/9√61+61/9+16/9+8/9√61+61/9
= ------------------------------------------------ = 154/9*(-9/45)=-154/45=-3 19/45
16/9-61/9
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Answers & Comments
D=64+180=244
x1=(8-2√61)/6=(4-√61)/3
x2=(8+2√61)/6=(4+√61)/3
x1/x2 + x2/x1 = ((4-√61)/3)/((4+√61)/3)+((4+√61)/3)/((4-√61)/3) = (4-√61)/(4+√61)+(4+√61)/(4-√61) = ((16-61)+(16+61))/((4+√61)(4-√61)) = 32/(16-61)=-32/45
3x^2 - 8x - 15=0
Δ=64-4*3*(-15)=244
√Δ=2√61
x1=(8-2√61)/6=4/3-1/3√61
x2=(8+2√61)/6=4/3+1/3√61
x1 x2 4/3-1/3√61 4/3+1/3√61
--- + --- = ---------------- + ----------------- =
x2 x1 4/3+1/3√61 4/3-1/3√61
(4/3-1/3√61)(4/3-1/3√61) (4/3+1/3√61)(4/3+1/3√61)
= --------------------------------- + ---------------------------------- =
(4/3+1/3√61)(4/3-1/3√61) (4/3-1/3√61)(4/3+1/3√61)
16/9-8/9√61+61/9+16/9+8/9√61+61/9
= ------------------------------------------------ = 154/9*(-9/45)=-154/45=-3 19/45
16/9-61/9