интеграл (x^3+2x^2+4x+3)/x+1 по dx. Created by dgtsghb. algebra-ru

x+1 по dx...

July 2022 1 6 Report

интеграл (x^3+2x^2+4x+3)/x+1 по dx

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bretkocё $\int\limits { \frac{x^3+2x^2+4x+3}{x+1} } \, dx =$

x³+2x²+4x+3 | x+1
- x³+x² ---------
---------- x²+x+3
x²+4x
-x²+x
-----------
3x+3
- 3x+3
---------
0

(x³+2x²+4x+3):(x+1)=x²+x+3

$\int\limits{ \frac{x^3+2x^2+4x+3}{x+1} } \, dx= \int\limits{(x^2+x+3} )\, dx= \frac{x^3}{3}+ \frac{x^2}{2}+3x+C$

napishite esse ili sochinenie na temu moe mnenie o tvorchestve hodasevicha poyasni

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dgtsghb August 2021 | 0 Ответы

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napishite esse ili sochinenie na temu moe mnenie o tvorchestve hodasevicha poyasni

kak mozhno obyasnit sleduyushee yavlenie pri skreshivanii golubyh andaluzskih kur v

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