f(x)=(x+1)(1-2x)=x-x*2x+1-2x=x-2x²+1-2x=-2x²-x+1.
f'(x)=(-2x²-x+1)'=(-2x²)'-(x)'+(1)'=-4x-1+0=-4x-1.
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f(x)=(x+1)(1-2x)=x-x*2x+1-2x=x-2x²+1-2x=-2x²-x+1.
f'(x)=(-2x²-x+1)'=(-2x²)'-(x)'+(1)'=-4x-1+0=-4x-1.