разложим на множители 3x²+10x+8
D=100-96=4
x1= (-10+2)/6= -4/3
x2= (-10-2)/6= -2
(3x-4)(x+2)/(x+1)(3x+4)= (x+2)/(x+1)
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разложим на множители 3x²+10x+8
D=100-96=4
x1= (-10+2)/6= -4/3
x2= (-10-2)/6= -2
(3x-4)(x+2)/(x+1)(3x+4)= (x+2)/(x+1)