разложим на множители 3x²+10x+8
D=100-96=4
x1= (-10+2)/6= -4/3
x2= (-10-2)/6= -2
(3x-4)(x+2)/(x+1)(3x+4)= (x+2)/(x+1)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
разложим на множители 3x²+10x+8
D=100-96=4
x1= (-10+2)/6= -4/3
x2= (-10-2)/6= -2
(3x-4)(x+2)/(x+1)(3x+4)= (x+2)/(x+1)