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lofi
@lofi
August 2022
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(x^2-1) (x+4)^2 (3x-12)=0
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filippov2002g
(x^2 - 1)(x + 4)^2(3x - 12)=0
(x-1)(x + 1)(x + 4)^2 * 3(x - 4)=0
x=1
x= -1
x = -4
x = 4
0 votes
Thanks 0
olya115153
(x²-1)(x+4)²(3x-12)=0
x²-1=0 или (x+4)²=0 или 3x-12=0
x²=1 x²+8x+16=0 3x=12
x=-1 D=0 x=4
x=1 x=4
ответ: -1; 1; 4
1 votes
Thanks 1
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Answers & Comments
(x-1)(x + 1)(x + 4)^2 * 3(x - 4)=0
x=1
x= -1
x = -4
x = 4
x²-1=0 или (x+4)²=0 или 3x-12=0
x²=1 x²+8x+16=0 3x=12
x=-1 D=0 x=4
x=1 x=4
ответ: -1; 1; 4