Докажите тождество :(5x/x-10+20x/x2-20x+100):4x-24/x2-100-25x\x-10=5x\4. Created by джастис. algebra-ru

x2-100-25x\x-10=5x\4...

джастис @джастис

July 2022 1 10 Report

Докажите тождество :(5x/x-10+20x/x2-20x+100):4x-24/x2-100-25x\x-10=5x\4

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sedinalana

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1)5x/(x-10)+20x/(x-10)²=(5x²-50x+20x)/(x-10)²=(5x²-30x)/(x-10)²=
=5x(x-6)/(x-10)²
2)5x/(x-10)² *(x-10)(x+10)/4(x-6)=(5x²+50x)/4(x-10)
3)(5x²+50x)/4(x-10)-25/(x-10)=(5x²+50x-100x)/4(x-10)=
=(5x²-50x)/4(x-10)=5x(x-10)/4(x-10)=5x/4

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