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(7/(x+1)) + ((x+4)/(2x-2)) = ((3x∧2-38) / (x∧2-1))
(7/(x+1)) + ((x+4)/(2x-2)) = ((3x∧2-38) / (x∧2-1))
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7/(x+1)+(x+4)/[2(x-1)]=(3x²-38)/[(x-1)(x+1)]ОЗ 2(x-1)(x+1)≠0⇒x≠1 x≠-1
14(x-1)+(x+4)(x+1)-2(3x²-38)=0
14x-14+x²+x+4x+4-6x²+76=0
-5x²+19x+66=0
5x²-19x-66=0
D=361+1320=1681
x1=(19-41)/10=-2,2
x2(19+41)/10=6