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belieber1204
@belieber1204
August 2022
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y=0.7x+5 y=x2+x-2 y=x+2/x2-2 Найдите область определения функции
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nKrynka
Решение
1) Y=0.7x+5
D(y) = R
2) y=x2+x-2
D(y) = R
3) y=x+2/x2-2
x
² - 2 ≠ 0
x² ≠ 2
x₁ = - √2
x₂ = √2
D(y) = (- ∞; - √2) ∪ (√2; + ∞)
2 votes
Thanks 5
nKrynka
D(y) = (- ∞; - √2) ∪ (- √2 ; √2) ∪ (√2; + ∞)
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Answers & Comments
1) Y=0.7x+5
D(y) = R
2) y=x2+x-2
D(y) = R
3) y=x+2/x2-2
x² - 2 ≠ 0
x² ≠ 2
x₁ = - √2
x₂ = √2
D(y) = (- ∞; - √2) ∪ (√2; + ∞)