Home
О нас
Products
Services
Регистрация
Войти
Поиск
dedj228
@dedj228
June 2023
1
8
Report
Срочно!!!!! даю 50балов!!! теорема Виэта.
x^2 - 13x-5=0; знайти: 1) 1/x1 + 1/x2;
2) x1^2x2 + x1x2^2
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Мишкабаянов
Решение на фото
//////
1 votes
Thanks 1
More Questions From This User
See All
dedj228
June 2023 | 0 Ответы
f19909e857f70c75dbd587fa59363c2c
Answer
dedj228
June 2023 | 0 Ответы
40 x 16x 0 x1x243
Answer
dedj228
June 2023 | 0 Ответы
9b4ce595a52757ba4e578e86e7378002
Answer
dedj228
January 2023 | 0 Ответы
30 63d8cc10c382c
Answer
×
Report "x2; 2) x1^2x2 + x1x2^2"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Решение на фото
//////