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maikochanturia
@maikochanturia
August 2022
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x^2-22|x|+120=0 reshenie
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pigift2p8aoz6
1)x>или =0
x^2-22x+120=0
a=1,b=-22,c=120
k=-11
D=121-120*1
D=1
x1=(22+1)/1
x1=23
x2=(22-1)/1
x2=21
2)x<0
x^2+22x+120=0
a=1,b=22,c=120
k=11
D=121-120*1
D=1
x1=(-22+1)/1
x1=-21
x2=(-21-1)/1
x2=-22
Ответ:x=-22,-21,21,23
0 votes
Thanks 1
maikochanturia
D1=11 и у вас получаерся 10,12
maikochanturia
нужнох1= 11-1\1=10 и х2=11+1=12
pigift2p8aoz6
дискриминант равен 1
pigift2p8aoz6
D1=k^2-ac
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Answers & Comments
x^2-22x+120=0
a=1,b=-22,c=120
k=-11
D=121-120*1
D=1
x1=(22+1)/1
x1=23
x2=(22-1)/1
x2=21
2)x<0
x^2+22x+120=0
a=1,b=22,c=120
k=11
D=121-120*1
D=1
x1=(-22+1)/1
x1=-21
x2=(-21-1)/1
x2=-22
Ответ:x=-22,-21,21,23