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utopia
@utopia
August 2021
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Решите неравенство:
1/x^2-2x ≤0
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oganesbagoyan
Verified answer
1/x² - 2x ≤ 0 ; ОДЗ : x ≠ 2
(2x³ -1)/x² ≥ 0;
2x³ -1 ≥ 0;
x ≥ 1/∛2 .
================
x∈ [ 1/∛2 ; ∞)
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Answers & Comments
Verified answer
1/x² - 2x ≤ 0 ; ОДЗ : x ≠ 2(2x³ -1)/x² ≥ 0;
2x³ -1 ≥ 0;
x ≥ 1/∛2 .
================
x∈ [ 1/∛2 ; ∞)