-x^2-2x≥0x^2+15x>0решить неравенства,заранее благодарю!. Created by anastasiaviltseva. algebra-ru

Объяснение:x*(x+2)≤0-∞__+__-2__-__0__+__+∞ ⇒Ответ: x∈[-2;0].x*(x+15)>0-∞__+__-15__-__0__+__+∞ ⇒Ответ: x∈(-∞;-15)U(0;+∞).

-x^2-2x≥0x^2+15x>0решить неравенства,заранее благодарю!...

anastasiaviltseva @anastasiaviltseva

July 2022 1 12 Report

-x^2-2x≥0
x^2+15x>0
решить неравенства,заранее благодарю!

Answers & Comments

sangers1959

Verified answer

Объяснение:

$\left [ {{-x^2-2x\geq 0\ |*(-1)} \atop {x^2+15x>0}} \right. \ \ \ \ \left [ {{x^2+2x\leq 0} \atop {x*(x+15)>0}} \right. \ \ \ \ \left [ {{x*(x+2)\leq 0} \atop {x*(x+15)>0}} \right. .$

x*(x+2)≤0

-∞__+__-2__-__0__+__+∞ ⇒

Ответ: x∈[-2;0].

x*(x+15)>0

-∞__+__-15__-__0__+__+∞ ⇒

Ответ: x∈(-∞;-15)U(0;+∞).

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