(x^2-2x+1)...

Tima888 @Tima888

August 2021 1 4 Report

2.Сократите дробь: (-0,4x^2-0,3x+0,7)/(x^2-2x+1)

Answers & Comments

julyap $\frac{-0.4x^2-0.3x+0.7}{x^2-2x+1} = \frac{(x-1)(x+1.75)}{(x-1)(x-1)}= \frac{x+1.75}{x-1} \\ -0.4x^2-0.3x+0.7=0/*10\\-4x^2-3x+7=0\\4x^2+3x-7=0\\D= 9+112=121\\ \sqrt{D} =11\\ x_{1} = \frac{-3+11}{8} = \frac{8}{8} =1\\ x_{2} = \frac{-3-11}{8} =- \frac{14}{8} =-1.75\\ x^{2} -2x+1=(x-1)^2$

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