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@271076
August 2022
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(x^2-2x)^2- 2(x^2 - 2x) - 3= 0
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hraky
T=x^2-2x
T^2-2t-3=0
D=4+12=16
T1=(2-4)/2=-1
T2=(2+4)/2=3
Теперь подставим Т1
Х^2-2х+1=0
D=4-4=0
X=1
Теперь подставим Т2
Х^2-2х-3=0
D=4+12=16
X1=(2-4)/2=-1
X2=(2+4)/2=3
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Answers & Comments
T^2-2t-3=0
D=4+12=16
T1=(2-4)/2=-1
T2=(2+4)/2=3
Теперь подставим Т1
Х^2-2х+1=0
D=4-4=0
X=1
Теперь подставим Т2
Х^2-2х-3=0
D=4+12=16
X1=(2-4)/2=-1
X2=(2+4)/2=3