[tex]\left \{ {{x^{2} - 2xy=12} \atop {x-y=4}} \right. \\\\\left \{ {{x^{2} - 2xy=12} \atop {y=x-4}} \right. \\\\\left \{ {{x^{2}- 2x(x-4)=12} \atop {y=x-4}} \right. \\x^{2} -2x^{2} +8x = 12\\-x^{2} +8x-12=0\\-x^{2} +2x+6x-12=0\\(-x^{2} +2x)+(6x-12)=0\\-x(x-2)+6(x-2)=0\\(x-2)(-x+6)=0\\x1=2 \\x2=6\\\\y1=2-4 \\y1=-2\\ y2=6-4 \\y2=2\\\\[/tex]

відповідь

(2;-2) , (6;2)