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MindZero
@MindZero
July 2022
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x^2-3x-10=0 решите уравнение.
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Silеncе
Verified answer
1 votes
Thanks 2
Kira091
Х^2-3х-10=0
D=b^2-4ac=(-3)^2-4*1*(-10)=9+40=49=7^2>0(уравнение имеет 2 корня)
Х1,2=(-b+|-корень из D)/2a=(-(-3)+|-корень из (7^2))/2*1
Х1=(3+7)/2=5
Х2=(3-7)/2=-2
Ответ:5;-2
2 votes
Thanks 0
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Answers & Comments
Verified answer
D=b^2-4ac=(-3)^2-4*1*(-10)=9+40=49=7^2>0(уравнение имеет 2 корня)
Х1,2=(-b+|-корень из D)/2a=(-(-3)+|-корень из (7^2))/2*1
Х1=(3+7)/2=5
Х2=(3-7)/2=-2
Ответ:5;-2