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Tiora
@Tiora
June 2022
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Найдите корни уравнения (с решением):
1/(x2-3x-3)+5/(x2-3x+1)=2
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nafanya2014
Verified answer
Х²-3х-3=t≠0
х²-3х+1=t+4≠0
t+4+5t=2t(t+4)
2t²+2t-4=0
t²+t-2=0
D=1-4·(-2)=1+8=9=3²
t=(-1-3)/2=-2 или t=(-1+3)/2=1
x²-3x-3=-2
x²-3x-1=0
D=(-3)²+4=13
x₁=(3-√13)/2 или х₂=(3+√13)/2
x²-3x-3=1
x²-3x-4=0
D=(-3)²+4·4=25
x₃=(3-5)/2=-1 или х₄=(3+5)/2=2
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Answers & Comments
Verified answer
Х²-3х-3=t≠0х²-3х+1=t+4≠0
t+4+5t=2t(t+4)
2t²+2t-4=0
t²+t-2=0
D=1-4·(-2)=1+8=9=3²
t=(-1-3)/2=-2 или t=(-1+3)/2=1
x²-3x-3=-2
x²-3x-1=0
D=(-3)²+4=13
x₁=(3-√13)/2 или х₂=(3+√13)/2
x²-3x-3=1
x²-3x-4=0
D=(-3)²+4·4=25
x₃=(3-5)/2=-1 или х₄=(3+5)/2=2