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lenanetrebkoGdjdd
@lenanetrebkoGdjdd
July 2022
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(x^2-3x)^2-14(x^2-3x)+40=0 ПОМОГИ ПЖ РЕШИТ НАДО методом заміни змінної
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koingrel
Verified answer
( х^2 - 3х )^2 - 14( х^2 - 3х ) + 40 = 0
Х^2 - 3х = а
а^2 - 14а + 40 = 0
D = 196 - 160 = 36 = 6^2
a1 = ( 14 + 6 ) : 2 = 10
a2 = ( 14 - 6 ) : 2 = - 4
1) x^2 - 3x - 10 = 0
D = 9 + 40 = 49 = 7^2
X1 = ( 3 + 7 ) : 2 = 5
X2 = ( 3 - 7 ) : 2 = - 2
2) x^2 - 3x + 4 = 0
D = 9 - 16 = - 7 ( < 0 )
Нет решений
Ответ 5 ; ( - 2 )
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Verified answer
( х^2 - 3х )^2 - 14( х^2 - 3х ) + 40 = 0Х^2 - 3х = а
а^2 - 14а + 40 = 0
D = 196 - 160 = 36 = 6^2
a1 = ( 14 + 6 ) : 2 = 10
a2 = ( 14 - 6 ) : 2 = - 4
1) x^2 - 3x - 10 = 0
D = 9 + 40 = 49 = 7^2
X1 = ( 3 + 7 ) : 2 = 5
X2 = ( 3 - 7 ) : 2 = - 2
2) x^2 - 3x + 4 = 0
D = 9 - 16 = - 7 ( < 0 )
Нет решений
Ответ 5 ; ( - 2 )