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еддпмаад
@еддпмаад
July 2022
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постройте график функции y=(2x^2+5x+2)/(x^2-4x+4)
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mikael2
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X²-4x+4=(x-2)² x=2 вертикальная асимптота. 2x²+5x+2=0 D=25-16=9 √9=3 x1=1/4[-5+3]=-1/2 x2=1/4[-5-3]=-2
график приложен.
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X²-4x+4=(x-2)² x=2 вертикальная асимптота. 2x²+5x+2=0 D=25-16=9 √9=3 x1=1/4[-5+3]=-1/2 x2=1/4[-5-3]=-2график приложен.