(x^2-5)^2-3(x^-5)=4=0. Created by kostynbai. algebra-ru

Пусть (х^2-5)=t, тогда:С учетом замены:и.Ответ:

(x^2-5)^2-3(x^-5)=4=0...

July 2022 1 8 Report

(x^2-5)^2-3(x^-5)=4=0

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Valtera Пусть (х^2-5)=t, тогда:
$t^2-3t-4=0, D=9+16=25=5^2 \\ t_1= \frac{3+5}{2} =4 \\ t_2= \frac{3-5}{2} =-1.$
С учетом замены:
$x^2-5=-1 \\ x^2=4, \\ x=б2$
и
$x^2-5=4 \\ x^2=9 \\ x=б3$ .
Ответ: $x=б2, x=б3$

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