[tex]\displaystyle\bf\\-x^{2} -5x-4\geq 0\\\\x^{2} +5x+4\leq 0\\\\(x+1)\cdot(x+4)\leq 0\\\\\\+ + + + + \Big[-4\Big] - - - - - \Big[-1\Big] + + + + + \\\\\\x\in\Big[-4 \ , \ -1\Big][/tex]
Наименьшее решение неравенства равно : - 4
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[tex]\displaystyle\bf\\-x^{2} -5x-4\geq 0\\\\x^{2} +5x+4\leq 0\\\\(x+1)\cdot(x+4)\leq 0\\\\\\+ + + + + \Big[-4\Big] - - - - - \Big[-1\Big] + + + + + \\\\\\x\in\Big[-4 \ , \ -1\Big][/tex]
Наименьшее решение неравенства равно : - 4