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tangliishu
@tangliishu
September 2021
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(x-9)(x^2-9)/(x^2-6x-27)
Пожалуйста, с решением.
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svetazuna
(х-9) * (х^2-9) / (х^2-6х+27) = (х-9)*(х-3)(х+3) / (х-9)(х+3) = х-3
**** х^2-6х-27 = 0,
Д=(-6)^2 + 4*1*(-27)= 36+108=144,
х1=(6+12)/2=9, х2=(6-12)/2=-3,
Значит: х^2-6х-27=(х-9)(х+3)
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Answers & Comments
**** х^2-6х-27 = 0,
Д=(-6)^2 + 4*1*(-27)= 36+108=144,
х1=(6+12)/2=9, х2=(6-12)/2=-3,
Значит: х^2-6х-27=(х-9)(х+3)