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ychenik36
@ychenik36
September 2021
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Сократить дробь 2x^2+5x-7/x^2-8x+7
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dianagorelova21
Решаем квадратные уравнения
1. Д = 25+4*2*7 = 81
х12 = (-5+-9)/4 = -3,5 и 1.
2. Д = 64-4*7 = 36
х12 = (8+-6)2 = 7 и 1
Числитель и знаменатель можно представить в виде:
=2(х+3.5)(х-1)/(х-7)(х-1) = 2(х+3.5)/(х-7) - ответ
1 votes
Thanks 6
yarovoe
(2x²+5x-7)/(x²-8x+7)=
2x²+5x-7=0 , x²-8x+7=0
D=5²-4·2·(-7)=25+56=81,√D=9
x₁=(-5-9)/4=-14/4=-7/2
x₂=(-5+9)/4=1
x²-8x+7=0 ,D=64-4·7=64-28=36,√D=6
x₁=(8-6)/2=1,x₂=(8+6)/2=7
(2x²+5x-7)/(x²-8x+7)= 2(x+7/2)(x-1)/(x-1)(x-7)
=(2x+7)/(x-7)
2 votes
Thanks 7
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Answers & Comments
1. Д = 25+4*2*7 = 81
х12 = (-5+-9)/4 = -3,5 и 1.
2. Д = 64-4*7 = 36
х12 = (8+-6)2 = 7 и 1
Числитель и знаменатель можно представить в виде:
=2(х+3.5)(х-1)/(х-7)(х-1) = 2(х+3.5)/(х-7) - ответ
2x²+5x-7=0 , x²-8x+7=0
D=5²-4·2·(-7)=25+56=81,√D=9
x₁=(-5-9)/4=-14/4=-7/2
x₂=(-5+9)/4=1
x²-8x+7=0 ,D=64-4·7=64-28=36,√D=6
x₁=(8-6)/2=1,x₂=(8+6)/2=7
(2x²+5x-7)/(x²-8x+7)= 2(x+7/2)(x-1)/(x-1)(x-7)
=(2x+7)/(x-7)