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кем3
@кем3
August 2022
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x2-x-42=0 помогите прошу
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bablbyзнает
Решение:
x^2-x-42=0
x1,2=(1+-D)/2*1
D=√(1-4*1*-42)=√(1+168)=√169=13
x1,2=(1+-13)/2
x1=(1+13)/2
x1=14/2
x1=7
x2=(1-13)/2
x2=-12/2
x2=-6
Ответ: (-6; 7)
0 votes
Thanks 1
fiofionina
Verified answer
Х2-х-42=0
х-42=0
х=0+42
х=42
5 votes
Thanks 5
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Answers & Comments
x^2-x-42=0
x1,2=(1+-D)/2*1
D=√(1-4*1*-42)=√(1+168)=√169=13
x1,2=(1+-13)/2
x1=(1+13)/2
x1=14/2
x1=7
x2=(1-13)/2
x2=-12/2
x2=-6
Ответ: (-6; 7)
Verified answer
Х2-х-42=0х-42=0
х=0+42
х=42