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Belfrid
@Belfrid
July 2022
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Решите уравнение: / - дробная черта ^2 - квадрат над числом
4/x-2 + x/x-4 = 1
x/x+3 + 4x+6/x^2+4x+3 = 0
x^2/x-3 - 45/x^2-x-6 + x/x+2 = x
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geniusFromRussia
1
ОДЗ х
2;4
4/x-2 +x/x-4=1
4(x-4)+x(x-2) / (x-2)(x-4) = 1
4x+16+x^2-2x / x^2 -4x-2x+8 = 1
x^2+2x+16 =x^2-6x+8
2x+16=-6x+8
2x+6x=8-16
8x=-8
x=-1
2 votes
Thanks 4
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Answers & Comments
ОДЗ х2;4
4/x-2 +x/x-4=1
4(x-4)+x(x-2) / (x-2)(x-4) = 1
4x+16+x^2-2x / x^2 -4x-2x+8 = 1
x^2+2x+16 =x^2-6x+8
2x+16=-6x+8
2x+6x=8-16
8x=-8
x=-1