x2+12x+27=0
x2-6x-27=0
x2+6x-27=0
x2-12x+36=0 Помогите решить по теореме Виетта!!!!!
x2-15x+36=0
x2+20x+36=0
x2+37x+36=0
x2-6x-27=0
x2+6x-27=0
x2-12x+36=0 Помогите решить по теореме Виетта!!!!!
x2-15x+36=0
x2+20x+36=0
x2+37x+36=0
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По теореме Виетта x₁+x₂=-b x₁*x₂=cх²+12х+27=0 b=12 c=27 x₁= -3 x₂ =-9
x2-6x-27=0 b=-6 c= -27 x₁= -3 x₂ =9
x2-12x+36=0 b=-12 c= 36 D=144-144=0 -тогда 1 корень x= 6
x2-15x+36=0 b=-15 c= 36 x₁= 12 x₂ =3
x2+20x+36=0 b=20 c=36 x₁= -18 x₂ =-2
x2+37x+36=0 b=37 c=36 x₁= -36 x₂ =-1