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msgauhar99
@msgauhar99
July 2022
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(x^2+2x+1)(x^2+2x-3)\<5
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svjatun
Введи новую переменную x^2+2x=t
(t+1)(t-3)<=5
t^2-2t-8<=0
t1=4 t2=-2
t∈(-2;4)
восстанови замену
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Answers & Comments
(t+1)(t-3)<=5
t^2-2t-8<=0
t1=4 t2=-2
t∈(-2;4)
восстанови замену