(x^2+3) в точке x0=0 Срочно пж, на кр сижу)))...

July 2022 1 19 Report

найти значения x при которых значения производной функции f(x)= (x+1)/(x^2+3) в точке x0=0
Срочно пж, на кр сижу)))

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NNNLLL54

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$f(x)=\frac{x+1}{x^2+3}\\\\f'(x)=\frac{x^2+3-(x+1)\cdot 2x}{(x^2+3)^2}=\frac{-x^2-2x+3}{(x^2+3)^2}=0\; \; \to \; \; x^2+2x-3=0\\\\x_1=-3\; ,\; x_2=1\; \; \; (teorema\; Vieta)\\\\Otvet:\; \; x=-3\; ,\; x=1\; .$

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