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Молсон
@Молсон
June 2022
1
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∫(−x^2−3x) dx
0 сверху
-3 снизу
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Vasily1975
Verified answer
=-∫x²dx-3∫xdx=-x³/3-3/2*x²=0-(27/3-27/2)=27/2-27/3=27/6=9/2
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Verified answer
=-∫x²dx-3∫xdx=-x³/3-3/2*x²=0-(27/3-27/2)=27/2-27/3=27/6=9/2