Ответ:
x²+23x+102=0
D = b^2 - 4ac = 23^2 - 4 × 1 × 102 = 529 - 408 = 121
x1 = (-b+- Квадратный корень из D)/(2a) = (-23+11)/(2×1) = - 12/2 = - 6
x2 = (-23-11)/(2×1) = - 34/2 = - 17
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Verified answer
Ответ:
x²+23x+102=0
D = b^2 - 4ac = 23^2 - 4 × 1 × 102 = 529 - 408 = 121
x1 = (-b+- Квадратный корень из D)/(2a) = (-23+11)/(2×1) = - 12/2 = - 6
x2 = (-23-11)/(2×1) = - 34/2 = - 17