x^2+3(√x)^2-4=0 x^2+(√x)^2-6=0. Created by wwwainurkz20. algebra-ru

x^2+3(√x)^2-4=0 x^2+(√x)^2-6=0...

July 2022 2 7 Report

x^2+3(√x)^2-4=0
x^2+(√x)^2-6=0

rasimagaliullov 1. х²+3(√х)²-4=0 х>0
х²+3х-4=0
по т.Виета х1*х2=-4
х1+х2=-3
х1=-4; х2=1
Ответ: х=1
2. х²+(√х)²-6=0 х>0
х²+х-6=0
По т.Виета х1*х2=-6
х1+х2=-1
х1=-3 х2=2
Ответ: х=2

0 votes Thanks 1

jandinok X^2+3(√x)^2-4=0
x^2+3x-4=0
D=9-4*1*-(4)=25
x(1)=(-3- √25):2=-4
x(2)=(-3+√25):2=1

0 votes Thanks 1

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