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July 2022
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x^2+4x-3>0
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acar
D=16+12=28=2√7
x1=(-4-2√7)/2=-2-√7
x2=-2+√7
x∈(-∞;-2-√7)∪(-2+√7;+∞)
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Answers & Comments
x1=(-4-2√7)/2=-2-√7
x2=-2+√7
x∈(-∞;-2-√7)∪(-2+√7;+∞)