Помогите пожалуйста решить (2/x^2-4 + 1/2x-x^2): 1/x^2+4x+4=. Created by AlexFil1. algebra-ru

x^2+4x+4=...

AlexFil1 @AlexFil1

July 2022 1 8 Report

Помогите пожалуйста решить
(2/x^2-4 + 1/2x-x^2): 1/x^2+4x+4=

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mukus13

Verified answer

$( \frac{2}{ x^{2} -4} + \frac{1}{2x- x^{2} } ): \frac{1}{ x^{2} +4x+4} =$
$( \frac{2}{(x-2)(x+2)} + \frac{x1}{x(2-x)} ): \frac{1}{(x+2)^2} =$
$(\frac{2}{(x-2)(x+2)} - \frac{1}{x(x-2)} )*(x+2^)^2=$
$\frac{2x-x-2}{x(x-2)(x+2)} *(x+2)^2= \frac{x-2}{x(x+2)(x-2)}*(x+2)^2=$
$\frac{x+2}{x}$

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AlexFil1 спасибо большое

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Answer

AlexFil1 August 2022 | 0 Ответы

Answers & Comments

Verified answer

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