Сделать программу для решения в Pascal
x^2+4x+5, если х<=2
f(x)=
1/(x^2+4x+5), если x>2
x^2+4x+5, если х<=2
f(x)=
1/(x^2+4x+5), если x>2
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Verified answer
Var x,f:real;begin
write('x = ');
readln(x);
if x<=2 then f:=x*x+4*x+5
else f:=1/(x*x+4*x+5);
writeln('f = ',f);
end.
Пример:
x = -3
f = 2