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mosik202
@mosik202
July 2022
1
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система: x+3y=1 / x2+4xy+y²=1
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Answers & Comments
lubana1
X=1-3y / х^2+4xy+y^2=1 ( вот это „/" это система)
(1-3y)^2+4(1-3y)y+y^2=1
y=0
y=-1
x=1-3•0
x=1-3•(-1)
x=1
x=4
Ответ: x1=1;y1=0 x2=4 y2=-1
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Answers & Comments
(1-3y)^2+4(1-3y)y+y^2=1
y=0
y=-1
x=1-3•0
x=1-3•(-1)
x=1
x=4
Ответ: x1=1;y1=0 x2=4 y2=-1