x^2+5...

July 2022 1 17 Report

Сравните g(2) и g(-2) если а)g(x)=1/x^2+5; б)g(x)=x/x^2+5; в)g(x)=-x/x^2+5

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irkarom

Verified answer

$a) g(2)=\frac1{x^2+5}=\frac1{2^2+5}=\frac1{4+5}=\frac{1}{9}\\
g(-2)=\frac1{x^2+5}=\frac1{(-2)^2+5}=\frac{1}{4+5}=\frac{1}{9}\\
g(2)=g(-2)\\
\\
b) g(2)=\frac{x}{x^2+5}=\frac{2}{2^2+5}=\frac2{4+5}=\frac{2}{9}\\
g(-2)=\frac{x}{x^2+5}=\frac{-2}{(-2)^2+5}=-\frac{2}{4+5}=-\frac{2}{9}\\
g(2)>g(-2)\\
\\
v)g(2)=-\frac{x}{x^2+5}=-\frac{2}{2^2+5}=-\frac2{4+5}=-\frac{2}{9}\\
g(-2)=-\frac{x}{x^2+5}=-\frac{-2}{(-2)^2+5}=\frac{2}{4+5}=\frac{2}{9}\\
g(2)$

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