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ksenon00
@ksenon00
July 2022
1
7
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Найти производную функции
е^5х
Sin(2x+1)
2/x^2
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DedushkaBake
(e^5x)'=(e^5x)*(5x)'=5e^5x
(sin(2x+1))'=(cos(2x+1))*(2x+1)'=2cos(2x+1)
2/x²=2x^(-2)=2(-2)x^(-2-1)=-4/x³
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Answers & Comments
(sin(2x+1))'=(cos(2x+1))*(2x+1)'=2cos(2x+1)
2/x²=2x^(-2)=2(-2)x^(-2-1)=-4/x³