Помогите решить a): (b/a^2-ab - 1/a-b) / (a+b/a^-ab - b/ab-b^2)
b) (3/(2-x^2)^2 + 2/x^2-4) * (x-2)^2 - 5x/x+2
b) (3/(2-x^2)^2 + 2/x^2-4) * (x-2)^2 - 5x/x+2
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11)b/a(a-b)-1/(a-b)=(b=a)/a(a-b)=-1/a
2)(a+b)/a(a-b)-b/b(a-b)=(ab+b²-ab)/ab(a-b)=b/a(a-b)
3)-1/a*a(a-b)/b=(b-a)/b
2
1)3/(x-2)²+2/(x-2)(x+2)=(3x+6+2x-4)/(x-2)²(x+2)=(5x+2)/(x-2)²(x+2)
2)(5x+2)/(x-2)²(x+2)*(x-2)²=(5x+2)/(x+2)
3)(5x+2)/(x+2)-5x/(x+2)=(5x+2-5x)/(x+2)=2/(x+2)