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annalokotok
@annalokotok
July 2022
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Решить уравнение
(2/х)+(10/(х²—2х))=(1+2x)/(x—2)
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Удачник66
Verified answer
Зачем спрашивать два раза одно и тоже?
Домножаем все на x^2 - 2x = x(x - 2)
2(x - 2) + 10 = (1 + 2x)*x
2x - 4 + 10 = x + 2x^2
x^2 - x - 6 = 0
(x - 3)(x + 2) = 0
x1 = -2; x2 = 3
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Answers & Comments
Verified answer
Зачем спрашивать два раза одно и тоже?Домножаем все на x^2 - 2x = x(x - 2)
2(x - 2) + 10 = (1 + 2x)*x
2x - 4 + 10 = x + 2x^2
x^2 - x - 6 = 0
(x - 3)(x + 2) = 0
x1 = -2; x2 = 3