помогите с нахождением производной от дроби (1-3x)/(x+2). Created by banality. algebra-ru

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November 2021 1 17 Report

помогите с нахождением производной от дроби (1-3x)/(x+2)

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dtnth

Verified answer

$(\frac{1-3x}{x+2})'=\\\\\frac{(1-3x)'*(x+2)-(1-3x)*(x+2)'}{(x+2)^2}=\\\\\frac{-3(x+2)-(1-3x)*1}{(x+2)^2}=\\\\\frac{-3x-6-1+3x}{(x+2)^2}=\frac{-7}{(x+2)^2}$

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Verified answer

3 chemu ravna0a6de4733c91fb8d2419378afce73761 62332

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