x^2+(x-5)(x+5)+x

July 2022 2 5 Report

x^2+(x-5)(x+5)+x<2x помогите

iljakz X² + x² - 25 + x - 2x < 0
2x² - x - 25 < 0
D = 1 + 200 = 201
x1 = (1-√201)/4
x2 = (1+√201)/4

x∈((1-√201)/4; (1+√201)/4)

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IrkaShevko

Verified answer

X^2 + x^2 - 25 + x -2x < 0
2x^2 -x - 25 <0
D = 1 + 200 = 201
x1 = (1+sqrt(201))/4
x2 = (1-sqrt(201))/4

Ответ x ринадлежит от (1-sqrt(201))/4 до (1+sqrt(201))/4 (это интервал)

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