Ответ:
[tex]\begin{cases} {x}^{2} {y}^{2} + x {y}^{3} = 192 \\ {x}^{3} y + {x}^{2} {y}^{2} = 96 \end{cases} [/tex]
[tex]\begin{cases}x {y}^{2} (x + y) = 192 \\ {x}^{2} y(x + y) = 96 \end{cases} [/tex]
[tex] \frac{x {y}^{2} (x + y)}{ {x}^{2}y(x + y) } = \frac{192}{96} [/tex]
сокращаем на общий делитель x+y;y;x и 96:
[tex] \frac{y}{x} = 2[/tex]
[tex]x \times \frac{y}{x} = 2x[/tex]
сокращаем на общий делитель x:
[tex]y = 2x[/tex]
[tex] {x}^{3} \times 2x + {x}^{2} \times {(2x)}^{2} = 96[/tex]
[tex] {x}^{3} \times 2x + {x}^{2} \times 4 {x}^{2} = 96[/tex]
[tex](1 + 2) \times 2 {x}^{2} \times x \times x = 96[/tex]
[tex]3 \times 2 {x}^{2} \times x \times x = 96[/tex]
[tex]6 {x}^{4} = 96[/tex]
делим обе стороны уравнения на 6:
[tex] {x}^{4} = 16[/tex]
[tex]x = ±2[/tex]
[tex]x = - 2 \\ x = 2[/tex]
[tex] {( - 2)}^{2} \times {y}^{2} + {( - 2)y}^{3} = 192 \\ {2}^{2} {y}^{2} + 2 {y}^{3} = 192[/tex]
[tex] {( - 2)}^{2} \times {y}^{2} + ( - 2) {y}^{3} = 192 \\ {2}^{2} {y}^{2} - 2 {y}^{3} = 192 \\ 4 {y}^{2} - 2 {y}^{3} = 192 \\ \div 2 \\ 2 {y}^{2} - {y}^{3} = 96 \\ 2 {y}^{2} - {y}^{3} - 96 = 0 \\ - {y}^{3} + 2 {y}^{2} - 96 = 0 \\ - {y}^{3} - 4 {y}^{2} + 6 {y}^{2} - 96 = 0 \\ - {y}^{2} (y + 4) + 6( {y}^{2} - 16) = 0 \\ - {y}^{2} (y + 4) + 6(y - 4)(y + 4) = 0 \\ - (y + 4)( {y}^{2} - 6(y - 4)) = 0 \\ - (y + 4)( {y}^{2} - 6y + 24) = 0 \\ (y + 4)( {y}^{2} - 6y + 24) = 0 \\ y + 4 = 0 \\ {y}^{2} - 6y + 24 = 0 \\ y = - 4 \\ y∉ℝ \\ y = - 4[/tex]
[tex] {2}^{2} {y}^{2} + 2 {y}^{3} = 192 \\ 4 {y}^{2} + 2 {y}^{3} = 192 \\ \div 2 \\ 2 {y}^{2} + {y}^{3} = 96 \\ 2 {y}^{2} + {y}^{3} - 96 = 0 \\ {y}^{3} + 2 {y}^{2} - 96 = 0 \\ {y}^{3} - 4 {y}^{2} + 6 {y}^{2} - 96 = 0 \\ {y}^{2} (y - 4) + 6( {y}^{2} - 16) = 0 \\ {y}^{2} (y - 4) + 6(y - 4)(y + 4) = 0 \\ (y - 4)( {y}^{2} + 6(y + 4)) = 0 \\ (y - 4)( {y}^{2} + 6y + 24) = 0 \\ y - 4 = 0 \\ {y}^{2} + 6y + 24 = 0 \\ y = 4 \\ y∉ℝ \\ y = 4[/tex]
[tex]y = - 4 \\ y = 4[/tex]
[tex](x_{1}, y_{1})=(-2, -4) \\ (x_{2}, y_{2})=(2,4)[/tex]
[tex]\begin{cases} {( - 2)}^{2} \times {( - 4)}^{2} + ( - 2) \times {( - 4)}^{3} = 192 \\ {( - 2)}^{3} \times ( - 4) + {( - 2)}^{2} \times {( - 4)}^{2} = 96 \end{cases} \\ \begin{cases} {2}^{2} \times {4}^{2} + 2 \times {4}^{3} = 192 \\ {2}^{3} \times 4 + {2}^{2} \times {4}^{2} = 96 \end{cases} [/tex]
[tex]\begin{cases} 192 = 192 \\ 96 = 96\end{cases} \\ \begin{cases} 192 = 192 \\ 96 = 96\end{cases} [/tex]
[tex](x_{1}, y_{1})=(-2, -4) \\ (x_{2}, y_{2})=(2, 4)[/tex]
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Answers & Comments
Ответ:
[tex]\begin{cases} {x}^{2} {y}^{2} + x {y}^{3} = 192 \\ {x}^{3} y + {x}^{2} {y}^{2} = 96 \end{cases} [/tex]
[tex]\begin{cases}x {y}^{2} (x + y) = 192 \\ {x}^{2} y(x + y) = 96 \end{cases} [/tex]
[tex] \frac{x {y}^{2} (x + y)}{ {x}^{2}y(x + y) } = \frac{192}{96} [/tex]
сокращаем на общий делитель x+y;y;x и 96:
[tex] \frac{y}{x} = 2[/tex]
[tex]x \times \frac{y}{x} = 2x[/tex]
сокращаем на общий делитель x:
[tex]y = 2x[/tex]
[tex] {x}^{3} \times 2x + {x}^{2} \times {(2x)}^{2} = 96[/tex]
[tex] {x}^{3} \times 2x + {x}^{2} \times 4 {x}^{2} = 96[/tex]
[tex](1 + 2) \times 2 {x}^{2} \times x \times x = 96[/tex]
[tex]3 \times 2 {x}^{2} \times x \times x = 96[/tex]
[tex]6 {x}^{4} = 96[/tex]
делим обе стороны уравнения на 6:
[tex] {x}^{4} = 16[/tex]
[tex]x = ±2[/tex]
[tex]x = - 2 \\ x = 2[/tex]
[tex] {( - 2)}^{2} \times {y}^{2} + {( - 2)y}^{3} = 192 \\ {2}^{2} {y}^{2} + 2 {y}^{3} = 192[/tex]
[tex] {( - 2)}^{2} \times {y}^{2} + ( - 2) {y}^{3} = 192 \\ {2}^{2} {y}^{2} - 2 {y}^{3} = 192 \\ 4 {y}^{2} - 2 {y}^{3} = 192 \\ \div 2 \\ 2 {y}^{2} - {y}^{3} = 96 \\ 2 {y}^{2} - {y}^{3} - 96 = 0 \\ - {y}^{3} + 2 {y}^{2} - 96 = 0 \\ - {y}^{3} - 4 {y}^{2} + 6 {y}^{2} - 96 = 0 \\ - {y}^{2} (y + 4) + 6( {y}^{2} - 16) = 0 \\ - {y}^{2} (y + 4) + 6(y - 4)(y + 4) = 0 \\ - (y + 4)( {y}^{2} - 6(y - 4)) = 0 \\ - (y + 4)( {y}^{2} - 6y + 24) = 0 \\ (y + 4)( {y}^{2} - 6y + 24) = 0 \\ y + 4 = 0 \\ {y}^{2} - 6y + 24 = 0 \\ y = - 4 \\ y∉ℝ \\ y = - 4[/tex]
[tex] {2}^{2} {y}^{2} + 2 {y}^{3} = 192 \\ 4 {y}^{2} + 2 {y}^{3} = 192 \\ \div 2 \\ 2 {y}^{2} + {y}^{3} = 96 \\ 2 {y}^{2} + {y}^{3} - 96 = 0 \\ {y}^{3} + 2 {y}^{2} - 96 = 0 \\ {y}^{3} - 4 {y}^{2} + 6 {y}^{2} - 96 = 0 \\ {y}^{2} (y - 4) + 6( {y}^{2} - 16) = 0 \\ {y}^{2} (y - 4) + 6(y - 4)(y + 4) = 0 \\ (y - 4)( {y}^{2} + 6(y + 4)) = 0 \\ (y - 4)( {y}^{2} + 6y + 24) = 0 \\ y - 4 = 0 \\ {y}^{2} + 6y + 24 = 0 \\ y = 4 \\ y∉ℝ \\ y = 4[/tex]
[tex]y = - 4 \\ y = 4[/tex]
[tex](x_{1}, y_{1})=(-2, -4) \\ (x_{2}, y_{2})=(2,4)[/tex]
[tex]\begin{cases} {( - 2)}^{2} \times {( - 4)}^{2} + ( - 2) \times {( - 4)}^{3} = 192 \\ {( - 2)}^{3} \times ( - 4) + {( - 2)}^{2} \times {( - 4)}^{2} = 96 \end{cases} \\ \begin{cases} {2}^{2} \times {4}^{2} + 2 \times {4}^{3} = 192 \\ {2}^{3} \times 4 + {2}^{2} \times {4}^{2} = 96 \end{cases} [/tex]
[tex]\begin{cases} 192 = 192 \\ 96 = 96\end{cases} \\ \begin{cases} 192 = 192 \\ 96 = 96\end{cases} [/tex]
[tex](x_{1}, y_{1})=(-2, -4) \\ (x_{2}, y_{2})=(2, 4)[/tex]