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bulgackovayuli
@bulgackovayuli
August 2022
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7 алгебра Сокращение алгебраических дробей
б) (x-4)*(x+2)/4x*(x+2)
в) 2p^2-8p/12-3p
г) 20a+35b/49b^2-16a^2
д) 25c^2-4a^2/4a^2-20ac+25c^2
е)x^2-9/x^3-27
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amina254
Б) (x-4)*(x+2)/4x*(x+2) =(х-4)/4х
в) 2p^2-8p/12-3p=2р(р-4)/3(4-р)=-2р/3
г) 20a+35b/49b^2-16a^2=5(4а+7b)/(7b+4a)(7b-4a)=5/(7b+4a)
д) 25c^2-4a^2/4a^2-20ac+25c^2=(5c-2a)(5c+2a)/(2a-5c)²=(5c+2a)/(5c-2a)
е)x^2-9/x^3-27=(x-3)(x+3)/(x-3)(x²+3x+9)=(x+3)/(x²+3x+9)
2 votes
Thanks 5
bulgackovayuli
Спасибо))
amina254
пожалуйста)))
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Answers & Comments
в) 2p^2-8p/12-3p=2р(р-4)/3(4-р)=-2р/3
г) 20a+35b/49b^2-16a^2=5(4а+7b)/(7b+4a)(7b-4a)=5/(7b+4a)
д) 25c^2-4a^2/4a^2-20ac+25c^2=(5c-2a)(5c+2a)/(2a-5c)²=(5c+2a)/(5c-2a)
е)x^2-9/x^3-27=(x-3)(x+3)/(x-3)(x²+3x+9)=(x+3)/(x²+3x+9)