x^3-49x=? 0,16y-3y=? 81x^2-9=0 16-4y^2=0
x^3-49x=x(x^2-49)=x(x-7)(x+7)
16-4y^2=0 4-y^2=0 (2-y)(2+y)=0 y=2 y=-2
81x^2-9=0 9x^2-1=0 (3x-1)(3x+1)=0 x=1/3 x=-1/3
0,16y-3y=-2.84y
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Answers & Comments
x^3-49x=x(x^2-49)=x(x-7)(x+7)
16-4y^2=0 4-y^2=0 (2-y)(2+y)=0 y=2 y=-2
81x^2-9=0 9x^2-1=0 (3x-1)(3x+1)=0 x=1/3 x=-1/3
0,16y-3y=-2.84y