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Anna1231
@Anna1231
July 2022
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x^3-4x^2+3=0 Объясните, как это возможно решить..
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oganesbagoyan
Verified answer
X³ -4x² +3 =0 ;
x=1 корень уравнения (1³ -4*1² +3 =
1- 4+ 3 =0
) .
x³ -x² -3x² +3 =0 ;
x²(x-1) -3(x²-1) =0;
x²(x-1) -3(x-1)(x+1) =0;
(x-1)(x² -3x-3) =0 ;
*************************************
или по столбикам
x³ -4x² +3 | x -1
|---------------
| x² -3x-3 x³ -4x² +3=(x-1)(x² -3x-3 )
2 votes
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Answers & Comments
Verified answer
X³ -4x² +3 =0 ;x=1 корень уравнения (1³ -4*1² +3 =1- 4+ 3 =0) .
x³ -x² -3x² +3 =0 ;
x²(x-1) -3(x²-1) =0;
x²(x-1) -3(x-1)(x+1) =0;
(x-1)(x² -3x-3) =0 ;
*************************************
или по столбикам
x³ -4x² +3 | x -1
|---------------
| x² -3x-3 x³ -4x² +3=(x-1)(x² -3x-3 )