(x+3)(5-x)log2(x+3)≥0. Created by shaltunyasha. algebra-ru

(x+3)(5-x)log2(x+3)≥0...

shaltunyasha @shaltunyasha

July 2022 1 13 Report

(x+3)(5-x)log2(x+3)≥0

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chamomile03

Verified answer

(x+3)(5-x)log₂(x+3)≥0
ОДЗ:
х+3>0
x>-3

Найдём нули функции:

х+3=0 5-х=0 log₂(x+3)=0
х=-3 х=5 log₂(x+3)=log₂1
х+3=1
х=-2

Наносим нули функции на числовую прямую и решаем методом интервалов:
+ - + -
-------[-3]-------------[-2]--------------[5]------->
/////////// //////////////////////

ОДЗ: ///////////////////////////////////////////
--------(-3)------------------------------------------>

Ответ: [-2; 5]

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