lim(3x+6)/(x^3+8) x стремится к -2. Created by deanonm. matematika-ru

(x^3+8) x стремится к -2...

pmahmudovaoyhgbo Lim= (3x+6)/(x^2+2^3)= 3(x+2)/(x+2)(x^2-2x+4)=3/(x^2-2x+4)=3/(4+4+4)=3/12=1/4

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ПрофиЗнания $\lim_{n \to \ -2} \frac{3(x+2)}{(x+2)( x^{2} -2x+4)} = \lim_{n \to \ -2} \frac{3}{( x^{2} -2x+4)} = \frac{3}{ (-2)^{2} -2*(-2)+4}$ = $\frac{3}{4+4+4} = \frac{3}{12} = \frac{1}{4}$

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